general chemistry chapter 6 chang 4
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3)Calculate ∆H(rxn)for the reaction:
5N2O4(l) +4N2H3CH3(l) = 12H2O(g) + 9N2(g) + 4CO2(g)
Given:
N2H3CH3(l) ∆H(rxn) = 54 kJ/mole
N2O4(l) ∆H(rxn) = -20kJ/mole
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